i.
1)
There are six planes of symmetry in this molecule, each bisecting the carbon atom and two hydrogen atoms and reflecting the two remaining hydrogen atoms on each other. Label the four hydrogen atoms for identification purposes:
Alternatively, place the methane molecule in a cube so that the carbon atom is at the center and the hydrogen atoms are at four vertices.
There are two planes of symmetry passing through each pair of parallel faces of the cube, one bisecting the two hydrogen atoms on one face and the other on the opposite face.
2)
There are three planes of symmetry in this molecule, each bisecting the carbon atom, the bromine atom, and one of the hydrogen atoms.
3)
There are two planes of symmetry in this molecule, one bisecting the two bromine atoms and the carbon atom and the other the two hydrogen atoms and the carbon atom.
4)
There is one plane of symmetry in this molecule, which bisects the two halogen atoms and the carbon atom.
5)
There are three planes of symmetry in this molecule, each bisecting the carbon atom, the hydrogen atom, and one of the bromine atoms.
6)
There is one plane of symmetry in the molecule, which bisects the hydrogen atom, the chlorine atom, and the carbon atom.
7)
There is no plane of symmetry in this molecule.
8 )
There are three planes of symmetry in this molecule.
i. Vertical plane perpendicular to the screen, bisecting the carbon-carbon double bond.
ii. Horizontal plane perpendicular to the screen, passing through the two carbon atoms.
iii. Plane of the screen, which slices the molecule.
9)
There is one plane of symmetry in this molecule, which is the plane of the screen, which slices the molecule.
10)
There are two planes of symmetry in this molecule.
i. Vertical plane perpendicular to the screen, bisecting the carbon-carbon double bond.
ii. Plane of the screen, which slices the molecule.
11)
There is one plane of symmetry in this molecule, which is the plane of the screen, which slices the molecule.
12)
There is one plane of symmetry in this molecule, which is the plane of the screen, which slices the molecule.
13)
There is one plane of symmetry in this molecule, which is the plane that bisects the two carbon atoms, the chlorine atom, and the hydrogen atom eclipsing the chlorine atom.
14)
There is one plane of symmetry in this molecule, which is the plane that bisects the two carbon atoms, the chlorine atom, and the hydrogen atom anti to the chlorine atom.
15)
There are two planes of symmetry in this molecule.
i. Vertical plane perpendicular to the screen, bisecting the carbon-carbon bond.
ii. Plane the bisects the two carbon atoms and the two chlorine atoms.
16)
There is one plane of symmetry in this molecule, which is the plane that bisects the two carbon atoms and the two chlorine atoms.
17)
There are an infinite number of planes of symmetry in this molecule, each passing through all four atoms.
18)
There are two planes of symmetry in this molecule.
i. Plane of the screen that bisects the three carbon atoms and the two hydrogens that are on the screen, reflecting the other two hydrogen atoms on each other.
ii. Horizontal plane perpendicular to the screen, passing through the three carbon atoms.
19)
There is one plane of symmetry in this molecule, which is the plane of the screen that bisects the three carbon atoms as well as the hydrogen atom and the methyl group on one terminal doubly bonded carbon (left) and reflecting the two hydrogen atoms on the other (right) on each other.
20)
There are two planes of symmetry in this molecule.
i. Plane of the screen that bisects the three carbon atoms and the two methyl groups reflecting the two hydrogen atoms on each other.
ii. Horizontal plane perpendicular to the screen, passing through the three carbon atoms.
21)
There is no plane of symmetry in this molecule.
22)
There is one plane of symmetry in this molecule, which is the plane perpendicular to the screen that passes through the methyl group.
23)
There is one plane of symmetry in this molecule, which is the plane that bisects the methyl group, C-1, and C-4 and reflects C-2 and C-6 on each other and C-3 and C-5 on each other.
24)
There is one plane of symmetry in this molecule, which is the plane that bisects the methyl group, C-1, and C-4 and reflects C-2 and C-6 on each other and C-3 and C-5 on each other.
25)
There is one plane of symmetry in this molecule, which the horizontal plane perpendicular to the screen that bisects the ring.
26)
There is no plane of symmetry in this molecule.
27)
There is no plane of symmetry in this molecule.
28)
There is no plane of symmetry in this molecule.
29)
There is no plane of symmetry in this molecule.
30)
There is one plane of symmetry in this molecule, which is the vertical plane perpendicular to the screen bisecting the bond linking C-1 and C-2.
31)
There is no plane of symmetry in this molecule.
32)
There are two planes of symmetry in this molecule.
i. Plane of the screen, which slices the molecule.
ii. Horizontal plane perpendicular to the screen, passing the carbon-oxygen bond.
33)
There is one plane of symmetry in this molecule, which is the plane of the screen, which slices the molecule.
34)
There is one plane of symmetry in this molecule, which is the vertical plane perpendicular to the screen that bisects the ring.
35)
There is one plane of symmetry in this molecule, which is the vertical plane on the screen, which bisects C-2 and C-5 and reflects the two methyl groups, C-1 and C-3, and C-4 and C-6 on each other.
36)
There is one plane of symmetry in this molecule, which is the vertical plane on the screen, which bisects C-2 and C-5 and reflects the two methyl groups, C-1 and C-3, and C-4 and C-6 on each other.
37)
There is no plane of symmetry in this molecule.
38)
There is no plane of symmetry in this molecule.
39)
There are two planes of symmetry in this molecule.
i. Horizontal plane perpendicular to the screen bisecting the ring.
ii. Vertical plane perpendicular to the screen bisecting the ring and the two methyl groups.
40)
There is one plane of symmetry in this molecule, which is the vertical plane on the screen, which bisects the two methyl groups, C-1, and C-4 and reflects C-2 and C-6 on each other and C-3 and C-5 on each other.
41)
There is one plane of symmetry in this molecule, which is the vertical plane perpendicular to the screen bisecting the screen and the two alkyl groups.
42)
There is one plane of symmetry in this molecule, which is the vertical plane on the screen, which bisects the two alkyl groups, C-1, and C-4 and reflects C-2 and C-6 on each other and C-3 and C-5 on each other.
43)
There is one plane of symmetry in this molecule, which is the vertical plane on the screen, which bisects the two alkyl groups, C-1, and C-4 and reflects C-2 and C-6 on each other and C-3 and C-5 on each other.
44)
There is one plane of symmetry in this molecule, which is the vertical plane perpendicular to the screen that bisects the two bridgehead carbons and the hydrogens on them.
45)
There is one plane of symmetry in this molecule, which is the vertical plane that passes through the two bridgehead carbons and the hydrogens on them.
46)
There are two planes of symmetry in this molecule.
i. Vertical plane perpendicular to the screen that passes through the two bridgehead carbons and the hydrogens on them.
ii. Horizontal plane perpendicular to the screen that bisects the bond connecting the two bridgehead carbons.
47)
There is no plane of symmetry in this molecule.
48)
There is one plane of symmetry in this molecule, which is the vertical plane perpendicular to the screen that bisects the ring.
49)
There are three planes of symmetry in this molecule, each a plane perpendicular to the screen bisecting the ring.
50)
There is one plane of symmetry in this molecule, which is the vertical plane perpendicular to the screen that bisects the ring.
